Check whether the given number is Armstrong

Define a function that check whether the given number is Armstrong

In this program, we will create a function to checks whether the given number is Armstrong/

Armstrong Number Algorithm

• Step1. Start
• Step2. import math
• Step3. Declare the variable n and read n
• Step4. define Armstrong function
• Step5. In Armstrong function
• Step6. Assign n to a
• Step7. Initialize sum to 0
• Step8. In while Loop, perform
  • d=n%10
  • sum+=d*d*d
  • n=math.floor(n/10)
• Step9. check the condition    sum==a
•  Step10  If the condition is a true print that given number is Armstrong number
• Step11. otherwise, print that given number is not Armstrong number
• Step12. Call Armstrong (n)  function
• Step13. End

Armstrong Number Example

import math
n=int(input("enter the number:"))
def armstrong(n):
    a=n              # 0  1  153  370   371   407
    sum=0
    while(n!=0):
        d = n%10
        sum += d**3
        n=math.floor(n/10)
    if(sum==a):
       print("given number is Armstrong number")
    else:
      print("given number is not Armstrong number")
armstrong(n)

Output:

>>> 
enter the number:155
given number is not Armstrong number
>>> 
>>> 
enter the number:153
given number is Armstrong number
>>> 

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