Find Unique Elements in Array Java algorithm and source code

How to find unique elements in array java

Write a java program that inputs 5 numbers, each between 10 and 100 inclusive. As each number is read display it only if it‘s not a duplicate of any number already read display the complete set of unique values input after the user enters each new value.

Description :

The main two conditions of these programs are

1. A number once read should not be read again.
2. The number we read should be in the range of 10 and 100.

The logic is as follows

1. If the number lies between 10 and 100,

Compare the recently read number with all the previously read numbers, if any number matches then declare that it a duplicate and ask the user to enter another number. Else declare that the number is not in the range of 10 and 100 and read another number.

Algorithm:

1. import java package
   1. import java.io.*;
   2. import java.util.*;
2. Create class Array
3. create main function
   1. public static void main(String ar[])
4. Declare variable
   1. int temp, i, flag = 0;
   2. int a[] = new int[10];
5. Scanner s = new Scanner(System.in);
6. Pass message to enter values
   1. System.out.println(” Enter values: “);
7. Use for loop and write a statement and also perform the comparison.
8. for( i = 0; i<5;)
   1. term = s.nestInt();
   2. flag = 0;
   3. if (temp > 10 && temp < 100)
      1. for int j= 0; j++)
         1. if (a[j] == temp)
            1. flag = 1;
      2. if( flag == 0);
         1. a [i] = temp;
         2. i++;
      3. else Print Number already exist, enter another value:
      4. else print number not in range
   4. Print Number in the array are:
9. for( int j = 0; j < 5; j++)
   1. print a[j];

Program to find Unique Array Element Source code:

import java.io.*;
import java.util.*;
public class Arrayy
{
            public static void main(String ar[])
            {
                        int temp,i,flag=0;
                        int a[]=new int[10];
                        Scanner s=new Scanner(System.in);
                        System.out.println("Enter values :  ");
                        for( i=0;i<5;)
                        {
                                    temp=s.nextInt();
                                    flag=0;
                                    if(temp>10 && temp<100)
                                    {
                                                for(int j=0;j<i;j++)
                                                            if(a[j]==temp)
                                                                        flag=1;
                                                if(flag==0)
                                                {
                                                            a[i]=temp;
                                                            i++;
                                                }
                                                else
                                    System.out.println("Number already entered. Enter another value : ");
                                    }
                                    else
                                    System.out.println("Number not in range. Enter another values : ");
                        }
                        System.out.println("Numbers in the array are : "); 
                        for(int j=0;j<5;j++)
                                    System.out.println(a[j]);
            }
}

Sample output :

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